This is a typical algebra problem with two unknowns, and we need to have two equations to solve the problem. Let X be the number of cows, and Y the number of chickens.
The number of cows plus the number of chickens equals 30:
X + Y = 30
Since cows have four legs and chickens have two legs, we can also have an equation for the number of legs.
4 X + 2 Y = 74
Rearranging the first equation we get
X = 30 - Y
Substituting X in the second equation gives us
4 × (30 - Y) + 2 Y = 74
120 - 4 Y + 2 Y = 74
-2 Y = 74 - 120 = -46
Y = 23
Everone is guessing so
This is humor quiz : so we should consider farmer's legs or even wife legs or ........