**Hard Mathematical Logic Puzzle Solution - 21 May**

A devotee visits 9 temples when he visits India. All these nine temples have one thing in common - there are 100 steps in every temple. The devotee puts Re.1 coin after climbing up every step. He does the same while climbing down every step. At each temple, the devotee offers half of his money from his pocket to god. In this way, his pocket becomes empty after his visit to 9th temple.

Can you calculate the total amount he had initially ?

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**Solution**146900

In such cases, we calculate from the last thing. Thus in this case, let us start counting from the 9th temple. Since, he must have offered 100 coins while climbing down stairs, it means that he must have offered Rs. 100 to god on the ninth temple and offered Rs. 100 while climbing up steps. Thus it is clear that he had Rs. 300 in his pocket before climbing the steps of the 9th temple.

Similarly, we will calculate for all the temples backwards.

Before eight temple: (300+100)*2 + 100 = 900

Before seventh temple: (900+100)*2 + 100 = 2100

Before Sixth temple: (2100+100)*2 + 100 = 4300

Before fifth temple: (4300+100)*2 + 100 = 8900

Before fourth temple: (8900+100)*2 + 100 = 18100

Before third temple: (18100+100)*2 + 100 = 36,500

Before second temple: (36500+100)*2 + 100 = 73300

Before first temple: (73300+100)*2 + 100 = 146900

Therefore he had Rs. 146900 initially.